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show that intergral using identity sin2x=2sinxcosx....please #5 Show al rk in yo

ID: 2876760 • Letter: S

Question


show that intergral using identity sin2x=2sinxcosx....please #5

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Explanation / Answer

(5) We know that 2 sin x cos x = sin 2x

So, sin x cos x = (1/2) sin 2x

sin x cos x dx = (1/2) sin 2x dx = (1/2) sin 2x dx = (1/2)[-cos(2x)]/2 + C = (-1/4) cos 2x + C