Time Remaining: 319:55 equation t for a line through the otleft parenthesis xtot
ID: 2878365 • Letter: T
Question
Time Remaining: 319:55 equation t for a line through the otleft parenthesis xtotoo Take a Test-Kaylen Scott Google Chrome https//www.mathxd.com/student/player Test cent erwin yes Fall 2016: MATH 364, Calculus III Section 1 Kaylen Scott Test: Final Examination Fall 2016 Time Remaining This Question: 3 pts 23 of 30 (22 complete v For the following trajectory, find the speed associated with the trajectory and then find the length of the trajectory on the given interval ,6 for o sts4 The speed associated with the trajectory is pe an exact answer, using radicals as needed) The length of the trajectory on the given interval is units Type an exact answer, using radicals as needed.) Enter your answer in each of the answer boxes s: A Systems Approach TempleExplanation / Answer
given r(t)=<4t3 ,-t3 ,6t3>
r'(t)=<12t2 ,-3t2 ,18t2>
speed =|r'(t)|
speed =[(12t2)2+(-3t2)2+(18t2)2]
speed =t2[(12)2+(-3)2+(18)2]
speed =t2[144+9+324]
speed=t2477
length of trajectory =[0 to 4]t2477 dt
length of trajectory =[0 to 4](1/3)t3477
length of trajectory =(1/3)(43-03)477
length of trajectory =(64/3)477
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2)g(w,x,y,z)=(cos(-7w-6x))(sin(8y+z))
gw=(-sin(-7w-6x))(-7-0)(sin(8y+z))
gw=7(sin(-7w-6x))(sin(8y+z))
gx=(-sin(-7w-6x))(0-6)(sin(8y+z))
gx=6(sin(-7w-6x))(sin(8y+z))
gy=(cos(-7w-6x))(cos(8y+z))(8+0)
gy=8(cos(-7w-6x))(cos(8y+z))
gz=(cos(-7w-6x))(cos(8y+z))(0+1)
gz=(cos(-7w-6x))(cos(8y+z))
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