When an object is dropped, the distance it falls in t seconds, assuming that air

Question

When an object is dropped, the distance it falls in t seconds, assuming that air resistance is negligible, is given by s(t) = 4.905t^2 where s(t) is in meters (m). If a stone is dropped from a cliff, assuming that air resistance is negligible, find the velocity and acceleration of the stone after it had been falling for 15 sec. The velocity of the stone is m/sec. (Type an integer or decimal rounded to two decimal places as needed.) The stone's acceleration is m/sec^2. (Type an integer or decimal rounded to two decimal places as needed.)

Explanation / Answer

s(t)=4.905t2

velocity, ds/dt=2*4.905t= 9.81 t

when t=15 secs we get

velocity,ds/dt=9.81*15=147.15 m/sec

b. acceleration, dv/dt=9.81

After 15 secs, the acceleration is 9.81m/sec2

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