e=0.768s-0.00004s^3 d=2 which will be d is 82 need clear readable detail please

Question

e=0.768s-0.00004s^3

d=2 which will be d is 82

need clear readable detail please

Problem The area of a region under a arwe is greater than the area of an inscribed rectangle and less than the area of a cr rcumscribed rectangle. Intuitively, we understand that somewhere between the inscribed and circumscribed here is a rectangle whose area is precisely equal to the area of the region under f (x)dx f (c)(b-a) The average value era function on the nterval Tai is determined by Average value z b-a SF rydx The efficiency r in at an automobile engine is given by e -0 where s is the speed en kmlhyof the car. Find the average efficiency with respect to the -3la kmih to s 8 d km/h Round the answer to one decima place speed for s Example: if lal -2 hen s 32 kay h and ildl 2 then 8 dl 82km/h

Explanation / Answer

given e=0.768s-0.00004s3 , s from 32 km/h to 82km/h

average efficiency =(1/(82-32))[32 to 82](0.768s-0.00004s3)ds

average efficiency =(1/50)[32 to 82](0.768s-0.00004s3)ds

average efficiency =(1/50)[32 to 82]((0.768/2)s2-(0.00004/4)s4)

average efficiency =(1/50)[32 to 82]((0.384)s2-(0.00001)s4)

average efficiency =(1/50)[((0.384)822-(0.00001)824)-((0.384)322-(0.00001)324)]

average efficiency =34.9

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