When BaCl2 2H2O is heated, the waters of hydration are driven off BaCI2 2H2O(s)

Question

When BaCl2 2H2O is heated, the waters of hydration are driven off BaCI2 2H2O(s) > BaCI2(s) +2H20(g) In this case, 2 moles of water are given off for every 1 mol of barium chloride residue formed. In this lab you will do the same thing, but for a compound in which you don't know how many waters of hydration are present, such as the following, where n represents the number of water molecules. NiSOA-nH20(s) NiSOA(s) + nH20(8) Suppose 1.082 g of NiSO4-nH20(s) is heated and, after cooling, the solid "residue" weighs .596 g. The residue is what's left after the water molecules are gone. Convert the lost mass to the number of moles of water which left the molecule. 486 mol 0.110 mol 00385 mol 0270 mol

Explanation / Answer

given weight of residue =0.596 g

weight of water which left the molecule=1.082-0.596 =0.486 g

molecular weight of water = 18 g/mol

number of moles of the water which left the molecule = 0.486/18

number of moles of the water which left the molecule = 0.0270 mol

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