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he can sell more necklaces, and if he raises the price than he sells fewer neckl

ID: 2891197 • Letter: H

Question

he can sell more necklaces, and if he raises the price than he sells fewer necklaces. The table below shows how the number n of necklaces sold in one day depends on the price p (in dollars). Price Number of necklaces sold 31 24 14 16 (a) Find a linear function of the form n = co + clp that best fits these data, using least squares. n=n(p) = (b) Find the revenue (number of items sold times the price of each item) as a function of price p. (c) If the material for each necklace costs Terry 5 dollars, find the profit (revenue minus cost of the material) as a function of price p P=P(p) = d) Finally, find the price that will maximize the profit.

Explanation / Answer

So, we get :
n = 47.643 - 2.112p ---> ANS

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Revenue is :
n * p

R = p(47.643 - 2.112p)

R = 47.643p - 2.112p^2 ---> ANS

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Profit :
Revenue - cost

Now, for p necklaces, he spends 5*p = 5p dollars for material cost

So,
P(p) = 47.643p - 2.112p^2 - (5p)

P(p) = 42.643p - 2.112p^2 ---> ANS

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d)
For max profit,
dP/dp = 0

42.643 - 4.224p = 0

p = 10.09 dollars approx

If this doesnt work
try 10.10 dollars