Can anyone help me with this problem please? Please see that the answer 196 m/s

Question

Can anyone help me with this problem please? Please see that the answer 196 m/s is wrong. I need help finding the right answer and why my answer is wrong. Someone else didn't read what I wrote and game me the same answer I already have. However, as you can see when I input the answer, it marks it as wrong. Thanks in advance to who ever helps me with this.

A projectile is fired with an initial speed of 190 m/s and angle of elevation 600. (Recall g 9.8 m/s2. Round your answers to the nearest whole number.) (a) Find the range of the projectile 3190 (b) Find the maximum height reached 1381 m (c) Find the speed at impact. 196 m/s

Explanation / Answer

Vfx = Vix = Vi*cos A

Vfx = 190*cos 60 deg = 95 m/sec

Total Time in air will be:

T = 2*V0*sin A/g

T = (2*190*sin 60 deg)/9.81 = 33.54 sec

Vfy = Viy + a*t

Vfy = 190*sin 60 deg - 9.81*33.54

Vfy = -164.48 m/sec

Now

Vf = sqrt (Vfx^2 + Vfy^2)

Vf = sqrt (95^2 + 164.48^2) = 189.94 m/sec = 190 m/sec

Or if you want to solve this problem using energy conservation, then

KEi + PEi = KEf + PEf

Since PEi and PEf = 0, So

KEi = KEf

which will be only possible when both launching speed and impact speed is same.

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