Can anyone help me with this problem please? I would like to Know the process on
ID: 3004015 • Letter: C
Question
Can anyone help me with this problem please? I would like to Know the process on how to get the answers because I thought i knew how to problems like these but not getting the right answer. Thank you in advance!
The way i was doing it is the with these steps.
1) find the position vector.
2)find the unit vector.
3 find the FBA, and the same process fro the other ones.
Am I doing it wrong?
A) Express force FBA as a Cartesian vector.
Express your answer in terms of the unit vectors i, j, and k. Use the 'vec' button to denote vectors in your answers. Express your answer using three significant figures.
B) Express force FCA as a Cartesian vector.
Express your answer in terms of the unit vectors i, j, and k. Use the 'vec' button to denote vectors in your answers. Express your answer using three significant figures.
C)Express force FDA as a Cartesian vector.
Express your answer in terms of the unit vectors i, j, and k. Use the 'vec' button to denote vectors in your answers. Express your answer using three significant figures.
Explanation / Answer
A>
the position vector for the force FBA is
first the coordinates of the A point is = 14 k , as its on the z axis os the x and the y component are 0
the coordinate of the B point is = 5i - 6j {z is zero as the point B is in the xy plane}
the position vector BA is = -5i + 6j + 14k
the unit vector is = [-5i + 6j + 14k]/sqrt[25 + 36 + 196]
the unit vector is = [-5i + 6j + 14k]/sqrt(257)
so the force FBA = 350*[-5i + 6j + 14k]/sqrt(257)
B>
point C = -3i-3j
point A = 14k
position vector CA = 3i + 3j - 14k
unit vecotr = 3i + 3j - 14k/sqrt(9+9+196) = [3i + 3j - 14k]/sqrt(214)
=> FCA = 500*[3i + 3j - 14k]/sqrt(214)
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