Thank you!! A discrete model 1 for Newton\'s Law of Cooling is yk+1 - yk = dtc

ID: 2900197 • Letter: T

Question

Thank you!!

A discrete model 1 for Newton's Law of Cooling is yk+1 - yk = dt*c*(ysur - yk) yk+1 - yk = dt*c*ysur - yk y'(t) = c (ysur - y(t)) y'(t) = c* ysur - y(t)) yk+1 - y = c (ysur - y(t)) A continuous model 1 for Newton's Law of Cooling is yk+1 - yk = dt*c*(ysur - yk) yk+1 - yk = dt*c*ysur - yk y'(t) = c (ysur - y(t)) y'(t) = c* ysur - y(t)) yk+1 - y = c (ysur - y(t)) A solution of the differential equation y' = (1/26)(70 - y) is y(t) = 70 + 130 e(-1/26)t y(t) = 70 + 130*exp(-t/26) y(t) = 70 +140 e(-1/26)t all of the above

Explanation / Answer

1) a

2) c

3) e

4) c

Navigate

Thank you!! :) n The Expert TA 1 Human-like G × Chegg Study Guided Sciuto × Kyli

Thank you!! As you know, protein kinase A phosphorylates amino acid residues on

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.

Thank you!! A discrete model 1 for Newton\'s Law of Cooling is yk+1 - yk = dt*c*

Question

Explanation / Answer

Related Questions

Navigate

Thank you!! A discrete model 1 for Newton\'s Law of Cooling is yk+1 - yk = dtc