It is desired to compare the average amount of time male and female college stud

Question

It is desired to compare the average amount of time male and female college students exercise per week. Random and independent samples were selected and the data was analyzed in the Statistix software and the following printout was generated Two-Sample T Tests for Exercise by Gender N Mean SD SE 42 5.7143 3.7370 0.5766 40 8.3250 4.7143 0.7454 Female Difference 2.6107 4.2417 0.9371 T-Tests for Mean Difference Null Hypothesis: difference O Alternative Hyp: difference O Lower Upper P 95% C.1.95% C.1. Method Variances DF T Equal 80 -2.79 0.0067-4.4756 -0.7458 Satterthwaite Unequal 74.3 -2.77 0.0071 4.4884 0.7331 Homogeneity of Variances Folded F Test F 39,41 1.59 0.0723 OF P If you were conducting a test of hypothesis to determine if there is a difference in the mean exercise times of all male and female students, which p-value would you interpret? 0 0071 00355 0067 5 6 9

Explanation / Answer

Answer : 0.0067

As the P value for homogeinity of variance is 0.0723 which is greater than 0.05, thus the variances are equal hence look at the pooled method with p value = 0.0067

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