Which sample size is considered reasonable such that the sampling distribution o
ID: 2909584 • Letter: W
Question
Which sample size is considered reasonable such that the sampling distribution of the r reasonably approximated by a normal distribution. a) both p and 1-p must be greater than 5 b) the population mean must be a percentage c) the sample size must be less than 30. d) the sample size must be greater than 30 uestions 12 to 15 refer to the following: The population of the ages of all US college students is skewed to the right with a me 27.4 years and a standard deviation of 5.8 years. A random sample of size 49 is selec the population. 12. Which standard distribution approximates the sampling distribution of the mean? a) normal b) binomialc)t d Chebychev 13. Determine a) 49 b) 27.4 c)5.8 d) 0.11837 e) 0.82857 14. Determine the a) 49 b) 27.4 0)5.8 d) 0.11837 e) 0.82857 15. Find the probability that the random sample of size 49 will have a sample mean age within one year of the population mean. (Round to nearest percent) a) 34% b) 68% c) 77% d) 88% Questions 16 to 18 refer to the following According to fitness magazine about 37% of the adults aged 18 to 54 use a herbal supplement. The sample size is 200. Calculate the mean of the sampling distribution of the proportion. a) p- 18 to 54 16. b) p 0.37 e)p-0.63d0.37 17. If sample of size 200 are selected from the population, calculate the standard error of the sampl distribution of the proportion. a) SE-0.23310 b) ?è-0.48280 c) SE-0.00241 d)?,-0.0341 S. Which standard distribution best approximates the sampling distribution of the proportion? a) normal b) binomial c) d) Chebychev Questions 19-22 refer to the output in Figure 1. The student newspaper NASPER reports w ing a class, 70% of the students are using the cell phone. The output in figure 1 reflects a fidence interval for a population proportion .64814,.75186 n 300 Figure 1 which value(s) represent the 95% confidence interval for the population proportion? ) 64814,.75185) b) .7 c)210 d) 300Explanation / Answer
12) option A is correct
13) mean =27.4 ; option B
14)std error of mean=5.8/sqrt(49)=0.82857 ; option E
15)P(-1/0.82857<Z<1/0.82857)=P(-1.21<Z<1.21)=77%
option C
16)
option D
17)std error =Sqrt(p(1-p)/n)=0.0341
option D
18)
optionA
19)
option A is correct
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