Chemical Oceanography Assignment 4 Due April 5, 2018 1. The half life (T1/2) of

Question

Chemical Oceanography Assignment 4 Due April 5, 2018 1. The half life (T1/2) of radioactive aluminum 29 (29Al)is 0.11 hours. A popular burrito shack wraps delicious burritos in sheets of aluminum foil, with each sheet containing 100 29Al atoms. The heat generated from radioactive decay keeps the burritos warm until they can be eaten. However, the level of radioactivity from 100 atoms of 29 Al is too high for human consumption. Only when the number of Al atoms reaches 42 can the burrito be safely handled without lead shielded gloves. While lead shielded gloves provide sufficient protection, it is very difficult to eat a burrito while wearing lead shielded gloves. Thus, each burrito is served with a napkin, upon which is written the equation for radioactive decay, as well as the various known terms N - Noe-*i No 100 atoms of 29A Ti/2 0.11 h, 6.6 min Patrons are told to solve for t to determine how long they should wait before handling the burrito. You are to solve for t using the above, provide your answer in both hours and minutes.

Explanation / Answer

N = NO e-lt N =42 NO = 100 t =? l = 0.693/ half life half life = 6.6 min l = 0.693/ 6.6 =0.105 42 = 100 x e-0.105 x t e-0.105 x t = 42/100 e-0.105 x t = 0.42 Taking log on both sides, -0.105 x t = log(0.42) -0.105 x t = -0.376 t = 0.376/0.105 = 3.58 mins They have to wait for 3.58 mins before handling the burrito.

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