Take a Test-stu hestos 1255 x Dr. N. Angulo-Mat 160-340A-(49369) Spring 2018 t:

Question

Take a Test-stu hestos 1255 x Dr. N. Angulo-Mat 160-340A-(49369) Spring 2018 t: Second Exam March 29, 2018 This Question 1 pt Tel the manimum numbee of zeros that the po?ynomial fusction may have Then use lule of Signs to determine how many postive and how many negative zeros the poly What is the maximum number of zos this polynomial buncion can have? How many posilive real zeros can the functon have? Cl (hea comena seprate answers as needed ) How matry negative real zeros can the function have? (Use a cemma to separate ancwers as soeded) in each of the a e DELL 8

Explanation / Answer

f(x) = 3x^3 - 6x^2 + x + 8

a) since the degree of polynomial is 3

maximum number of zeros this polynomial can have is 3

b) total number of sign changes in f(x) is 2

so, it can have 0,2 positive real zeros

c) f(-x) = -3x^3 - 6x^2 -x + 8

total sign changes in f(-x) is 1

so, it can have 1 negative real zero

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