Approximately 8% of people are left-handed. If two people areselected at random,

Question

Approximately 8% of people are left-handed. If two people areselected at random, what is the probability of the followingevents? 1.P(Both are right-handed) = ? 2.P(Both are left-handed) = ? 3.P(One is right-handed and the other is left-handed) =? 4.P(At least one is right-handed) = ? Approximately 8% of people are left-handed. If two people areselected at random, what is the probability of the followingevents? 1.P(Both are right-handed) = ? 2.P(Both are left-handed) = ? 3.P(One is right-handed and the other is left-handed) =? 4.P(At least one is right-handed) = ?

Explanation / Answer

Approximately 8% of people are left-handed. If two people areselected at random, what is the probability of the followingevents? 1.P(Both are right-handed) = ?
.92*.92=.846
2.P(Both are left-handed) = ?
.08*.08=.0064
3.P(One is right-handed and the other is left-handed) = ?
it can be either first being right and second being left and viceversa, and they both have the same prob so
2*.92*.08=.147
4.P(At least one is right-handed) = ?
there are 3 cases:
both right handed = .92*.92=.846
first right handed second left handed=.0736
first left and second right=.0736
so total= .993

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