The Canada Safet Council reported the 9.8% of Canadian driversread while driving

Question

The Canada Safet Council reported the 9.8% of Canadian driversread while driving. if 502 drivers are selected at random, find theprobability that exactly 41 will admit to reading whiledriving.
(a)19.28%
(b)35.84%
(c)2.81%
(d)70.73% I am not too sure what method to use for this problem, is itthe Binomial Method? The Canada Safet Council reported the 9.8% of Canadian driversread while driving. if 502 drivers are selected at random, find theprobability that exactly 41 will admit to reading whiledriving.
(a)19.28%
(b)35.84%
(c)2.81%
(d)70.73% I am not too sure what method to use for this problem, is itthe Binomial Method?

Explanation / Answer

p=0.098 , n=502 X~Binomial (n=502, p=0.098) Using Binomial approximate Normal distribution. X~Normal(=n*p=502*0.098=49.196,=n*p*(1-p)=502*0.098*(1-0.098) =6.66) P(X=41) = P(40.5

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