Can someone help me put together my SPSS information into the proper APA format?

Question

Can someone help me put together my SPSS information into the proper APA format?

Here is an example of what they are asking for.

Example:

            Freshmen and Sophomores were expected to score significantly higher on a measure of depression than were Juniors and Seniors. A One-Way ANOVA was used to test the hypothesis leading to the rejection of the null hypothesis, indicating a significant difference between the means, F(3, 96)=4.61, p<.05. Tukey post-hoc tests revealed that Freshmen (M=9.65, SD=1.59) were significantly more depressed than were Juniors (M=4.59, SD=.98) and Seniors (M=5.68, SD=1.22) but not significantly different from Sophomores (M=8.95, SD=1.43). Also, Sophomores were significantly more depressed than Juniors and Seniors but not Freshman.  

I should have three of these "paragraphs" made from the information I already answered below.

Answer the following questions for each hypothesis:

Older and younger females will report different levels of tangible help.

What is the null hypothesis tested?

Females who live in the dorms, females who live in apartments or houses, and females who live with their parents will report different levels of tangible help.

What is the null hypothesis tested?

Age group and where they live now will interact.

What is the null hypothesis tested?

1. State what hypothesis was tested.

1. Older and younger females will report different levels of tangible help.

2. Females who live in the dorms, females who live in apartments or houses, and females who live with their parents will report different levels of tangible help.

3. Age group and where they live now will interact.

2. State what test was used.

F-test, Tukey HSD teat and Levene's Test of Equality was used.

3. What decision did you make? Reject the null or retain (fail to reject) the null?

1. Older and younger females will report different levels of tangible help. - F-stat is 1.155 and the p-value is 0.285 which is greater than 0.05, so we fail to reject the null hypothesis.

2. Females who live in the dorms, females who live in apartments or houses, and females who live with their parents will report different levels of tangible help. F-stat is .157 and the p-value is 0.855 which is greater than 0.05, so we fail to reject the null hypothesis.

3. Age group and where they live now will interact. F-stat is .151 and the p-value is 0.860 which is greater than 0.05, so we fail to reject the null hypothesis.

4. Were the groups significantly different from each other? - As p-value < 0.05, we fail to reject the null hypothesis and the groups are not significantly different from each other

5. Report the means and standard deviations for each group.

For Living in Dorm and Age group Younger, mean = 54.92, Std deviation = 7.259
For Living in Dorm and Age group older, mean = 57.60, Std deviation = 6.096
For Living in Apartment or House and Age group Younger, mean = 54.78, Std deviation = 5.357
For Living in Apartment or House and Age group older, mean = 55.28, Std deviation = 7.591
For Living with Parents and Age group Younger, mean = 54.57, Std deviation = 14.124
For Living with Parents and Age group older, mean = 57.11, Std deviation = 5.960

6. Put numbers in APA format:

a. General Format: symbol for the test (df)= obtained value, p> or < significance level

For Corrected Model, df = 5 and p (.886) > significance level(0.05)
For, Whlive, df= 2 and p (.855) > significance level(0.05)
For, Agegrp, df= 1 and p (.285) > significance level(0.05)

For whlive * agegrp, df= 2 and p (.86) > significance level(0.05)

b. Specific for F Tests: F(2, 99)=3.98, p<.05

For Corrected Model, F(2,94)=0.342, p>0.05
For, Whlive, F(2,94)=0.157, p>0.05
For, Agegrp, F(1,94)=1.155, p>0.05

For whlive * agegrp, F(2,94)=0.151, p>0.05

c. Now you need to discuss which of the mean comparisons done by the Tukey were significant. You do not need to report numbers just which groups were different from each other, if any.

The simultaneous pairwise comparisons indicate that the differences of means are not significantly different from 0 as their confidence intervals include 0.

7. Report Effect Size (if known)

SD(pooled) = sqrt(sqr(SD1) + sqr(SD2)/2) = sqrt(sqr(9.367) + sqr(6.759)/ 2) = 8.167

Cohen's d effect size = Mean2 - Mean1 / SD(pooled)

= (56.34-54.79) /  8.167 = 0.1897

Explanation / Answer

1   Always remember the null hypothesis you are testing should be absolutely neutral.

     Where HO= Older female

                   HY = younger female

2. HD = females living in dorms

HA   =   females who live in apartments .

HP   =   females who live with their parents.

So the HO : HD = HA = HP

3. HA1 = Fe,males by age group.

HL1    = living places of female.

HO : HA1 = HL1 ‘

       = No interaction in age and where they live now.

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