SPSS Module 6 Assignment-ANOVA General Instructions: In this assignment, we will
ID: 2925036 • Letter: S
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SPSS Module 6 Assignment-ANOVA General Instructions: In this assignment, we will be examining 2 One-Way ANOVAs and interpreting the results. As with previous assignments, the Aspelmeier and Pierce text does a wonderful job of explaining how to actually run the tests in Chapter 8. Follow their instructions for interpreting the SPSS output results I have given you for this assignment. ANOVA The researchers want to compare the mean rating of Emotional Support of the groups of where students currently live (1-Dorm, 2-Apartment or House with Peers or Alone, 3-Parents). Also, researchers think that the family composition of the house people grow up in will influence the amount of loyalty females will reported with their closest female friends. As we learned from the text and the PPTs, we know these research situations require the use of the ANOVA. Here are the researchers' hypotheses 1. The researchers think that students who live at home will report different levels of emotional support from their closest female friends than those students who live either in the dorms or in an apartment or house with peers or alone The researchers also believe that females will report differing levels of loyalty with their closest female friends based on the family composition of the house in which they grew up 2. Use the SPSS data to and make conclusions. 1. For this assignment, we will need to run 2 One Way ANOVA Tests: one comparing levels of where students currently live and one comparing the family composition of the house in which they grew up. Unlike the last assignment, our groups are already formed. We also need to run the Tukey multiple comparison procedures. Additionally, we need to create a graph for each hypothesis. 2. 3. Hypotheses: 1. The researchers think that students who live at home will report different levels of emotional support from their closest female friends than those students who live either in the dorms or in an apartment or house with peers or alone. The researchers also believe that females will report differing levels of loyalty with their closest female friends based on the family composition of the house in which they grew up. 2. Descriptives EmoSupport 95% Confidence Interval for Mean Std. Upper Bound Std. Lower Min Max 37 64 40 64 N Mean Deviation Error Bound Dorm Apartment or House with Peers or Parents Total 34 5744 7.1661.229 54.94 59.94 34 56.09 7.0121.203 53.64 58.53 3255.75 100 56.44 10.4791.852 51.97 59.53 9 64 8.272 827 54.80 58.08 9 64Explanation / Answer
1.
a. Null Hypothesis H0: The level of emotional support from their closest female friends for students who live either in the home, dorms or in an apartment or house with peers or alone are same.
b.
Yes, we can assume equal variances, as the p-value of Levene's test for equality of variances is greater than 0.05 and we fail to reject the null hypothesis and is significant.
c.
The students who live at home are expected to have different level of emotional support from their closest female friends than those students who live either in the dorms or in an apartment or house with peers or alone.
A one-way ANOVA was used to test the hypothesis leading to the acceptance of null hypothesis, indicating no difference between the means, F(2,97)=0.386, p > 0.05. Tukey post-hoc tests revealed that for all house types, the confidence interval contains 0, so emotional support from their closest female friends has the same levels for students living in different home types.
2.
a. Null Hypothesis H0: The levels of loyalty of females with their closest female friends based on the family composition of the house in which they grew up are same.
b.
No, we cannot assume equal variances, as the p-value of Levene's test for equality of variances is less than 0.05 and we reject the null hypothesis and is not significant.
c.
The females are expected to have different levels of loyalty with their closest female friends based on the family composition of the house in which they grew up. A one-way ANOVA was used to test the hypothesis leading to the acceptance of null hypothesis, indicating no difference between the means, F(2,97)=2.230, p > 0.05. Tukey post-hoc tests revealed that for all house types, the confidence interval contains 0, so levels of loyalty of females with their closest female friends based on the family composition of the house in which they grew up are same.
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