H 333 (A): Probability & Statistics. Examination #1 (Fall 2008) 3. Of patients g

Question

H 333 (A): Probability & Statistics. Examination #1 (Fall 2008) 3. Of patients going to a primary care physician's (PCP's) office, 30% are referred to a specialist, 40% require lab work, and 35% require neither lab work nor a referral to a specialist. (a) Determine the probability that a visit to a PCP's office results in both lab work and a (b) Consider the case when five records of patients' visits to a PCP's office are selected (c) Consider the case when another five records of patients' visits to a PCP's office are referral to a specialist. (7 pts) at random. Find the probability that all 5 of them are referred to a specialist. (7 pts) selected at random. Find the probability that at least one of them is referred to a specialist. (6 pts) 4. A study of automobile accidents produced the following results:

Explanation / Answer

Here we are given that P( specialist )= 0.3 , P( lab work ) = 0.4 and P( neither of the two ) = 0.35

a) Now as we are given that: P( neither of the two ) = 0.35, therefore

P( specialist or lab work ) = 1 - P( neither of the two ) = 1 - 0.35 = 0.65

Using addition law of probability, we get:

P( specialist and lab work ) = P( specialist ) + P( lab work ) - P( specialist or lab work )

P( specialist and lab work ) = 0.3 + 0.4 - 0.65 = 0.05

Therefore 0.05 is the required probability here.

b) Probability that all 5 of them are referred to a specialist is computed as:

= 0.3*0.3*0.3*0.3*0.3

= 0.35

= 0.00243

Therefore 0.00243 is the required probability here.

c) Probability that at least one of the next 5 is referred to the specialist

= 1 - Probability that no one is referred to the specialist

= 1 - (1 - 0.3)5

= 0.83193

Therefore 0.83193 is the required probability here.

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.