Consider the following binomial random variables. (a) The number of tails seen i
ID: 2927351 • Letter: C
Question
Explanation / Answer
Sol:
For binomial distribution
mean=np
std deviation=sqrt(npq)
p---prob of success
n--no of trials
q---prob of failure
q=1-p
p=1/2
q=1-1/2=1/2
n=46
mean=46*1/2=23
std deviatoon=sqrt(46*1/2*1/2)
=sqrt(11.5)
=3.39
solutionbi:
mean=np=48*0.07
=3.36
solutionbii:
std dev=sqrt(npq)
=sqrt(48*0.07*0.93)
=sqrt(3.1248)
=1.77
Solutionci:
mean=407*19%=407*0.19=77.33
Solutioncii
stddev=sqrt(npq)
=sqrt(407)(0.19)(1-0.19)
=sqrt(62.6373)
=7.91
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