An Internet survey reported that 59% of users of a popular social networking web

Question

An Internet survey reported that 59% of users of a popular social networking website have taken a voluntary break from that site of several weeks or more at one time or another. The survey contacted 1008 adults living in the United States by landline and cell phone. The 525 people who reported that they were users of this particular site were asked, "Have you ever voluntarily taken a break from the site for a period of several weeks or more?" A total of 310 responded, "Yes, I have done this." From this survey, rounded to four decimal places, = (Round your final answer to five decimal places.) The standard error is the following p(1-p) The z* critical value for 95% confidence, rounded to two decimal places, is z*- the following. (Round your final answer to 5 decimal places.) , so the margin of error is m = 1.96SE = 1.96 The confidence interval is the following. (Round your answer to two decimal places.) p±m=0.59 ± % and we are 95% confident that, rounded to the nearest percent, between this particular social networking site took a voluntary break of several weeks or more % of users of

Explanation / Answer

a)

X = 310 , n = 525

p^ =310/525 = 0.590476

SE(p^) =sqrt(0.590476 * (1 -0.590476 ) / 525)

= 0.021461553

z-critical for 95% confidence

z* = 1.96

m = 1.96 * 0.021461553 = 0.042064645

confidence interval

= 0.59 +-   (0.42065)

we are 95 % confident that (0.548411546 , 0.632540835)

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