Question 1,3.1-2.1 The following is a set of data from a sample of n-5. 52789 a.

Question

Question 1,3.1-2.1 The following is a set of data from a sample of n-5. 52789 a. Compute the mean, median, and mode. b. Compute the range, variance, standard deviation, and coefficient of variation. c. Compute the Z scores. Are there any outliers? Stu d. Describe the shape of the data set. a. Select the correct choice below and, if necessary, ill in thte answer box to complete your choice. Gra O A. The mean is Type an integer or a decimal. Do not round. Use a comma to separate answers as needed) O B. There is no solution. eTe Disc Click to select and enter your answer(s) and then click Check Answer Clear Al Coul 13pertaining

Explanation / Answer

1,3.1-2.1

the following data 5,2,7,8,9

sample size n=5

a.

Mean of the given data = sum of observations/ number of observations

= 5+2+7+8+9/5

= 31/5

= 6.2

median is the middle most number in the given data because n=5 odd number,

given data arranged in ascending order 2,5,7,8,9 so that

median =7

  

mode is above given data is no mode because not repeated any value

2,3.1-2.1

given data 33,34,28,28,30,30,25,26,26,26,27,23,31

Mean of the given data = sum of observations/ number of observations

=(33+34+28+28+30+30+25+26+26+26+27+23+31)/13

= 28.2307

given data arranged in ascending order = 23,25,26,26,26,27,28,28,30,30,31,33,34

median is the middle most number in the given data because n=13 odd number

median is 28

mode is above given data is 26 because repeated value

  

3,3.1-2.1

  

given data 9.72,5.88,7.95,5.85,8.78,3.77,8.09,8.29,10.55,6.63,5.64,4.04,9.97,6.08,5.37

Mean of the given data = sum of observations/ number of observations

=(9.72+5.88+7.95+5.85+8.78+3.77+8.09+8.29+10.55+6.63+5.64+4.04+9.97+6.08+5.37)/15

=7.1073

median is the middle most number in the given data because n=15 odd number

given data set arranged in ascending order then we get middle most number is median

3.77, 4.04,5.37,5.64,5.85,5.88,6.08,6.63,7.95,8.09,8.29,8.78,9.72,9.97,10.55`

median =6.63

  

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