In a survey of women in a certain country (ages 20-29), the mean height was 64.9

Question

In a survey of women in a certain country (ages 20-29), the mean height was 64.9 inches with a standard deviation of 2.74 inches. Answer the following questions about the specified normal distribution. (b) What height represents the first quartile? unlatn, an..nnnn 4.nl.th n-In hin ..r,,i, .^ u. ni.. AfthA ·nhIn nn n^ (a) The height that represents the 95th percentile is 69.41 inches. (Round to two decimal places as needed) inches (b) The height that represents the first quartile is Rnund tn hwin decimal nlares as needed) Enter your answer in each of the answer boxes

Explanation / Answer

Solution:-
b) Find the z-value with a left tail of 25%: z = -0.6745

x = -0.6745*2.74+64.9 = 63.05 inches

the height that represents the first is 63.05 inches.

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