In a survey of women in a certain country (ages 20-29), the mean height was 64 7
ID: 3316643 • Letter: I
Question
In a survey of women in a certain country (ages 20-29), the mean height was 64 7 inches with a standard deviation of 2.75 inches Answer the following questions about the specified normal distribution (a) What height represents the 95th percentile? (b) What height represents the first quartile? Click to view page 1 of the table. Click to view inches. (a) The height that represents the 95th percentile (Round to two decimal places as needed) (b) The height that represents the first quartie lS·inches (Round to two decimal places as needed.)Explanation / Answer
a) z score corresponding to 95th percentile = 1.645
Hence,
Height corresponds to 95th percentile = 64.7 + 1.645*2.75 = 69.22
b) z score corresponding to 1st quartile = -0.67
Hence,
Height corresponds to 95th percentile = 64.7 - 0.67*2.75 = 62.86
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