Chrome File Edit View History Bookmarks People Window Help Do said 9 ) A U.S. 30

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Chrome File Edit View History Bookmarks People Window Help Do said 9 ) A U.S. 30% D Sat Oct 21 5:10 PM Q E MindTap - Cengage Learning O ng.cengagecom/static/nb/ui/index.html?nbld=614983&nbNodeld;=225576193&deploymentld;=57360077114017630615688974&elSBN; -9781337115377#I&parentld;=225576640 - L MINDTAP I from Congage Chapter 8 Assignment Due on Tomorrow at 11:59 PM EDT Save Submit Assignment for Grading Questions Exercise 08.41 Question 8 of 11 Check My Work O Exercise 8.41 10. o fewer young people are driving. In 1983, 87% of 19-year-olds had a drivers license. Twenty-five years later that percentage had dropped to 75% (University of Michigan Transportation Research Institute website, April 7, 2012). Suppose these results are based on a random sample of 1200 19-year-olds in 1983 and again in 2008. 11. a. At 95% confidence, what is the margin of error and the interval estimate of the number of 19-year-old drivers in 1983? Round your intermediate answers to four decimal places. Margin of error = ® (four decimal places) Interval estimate (to four decimal places) to b. At 95% confidence, what is the margin of error and the interval estimate of the number of 19-yearold drivers in 2008? Round your answers to four decimal places. Margin of error = Interval estimate G. Is the margin of error the same in parts (a) and (b)? No Why, or why not? The input in the box below will not be graded, but may be reviewed and considered by your instructor. 1 0 1 0 000 D Eg ON FOX ELECCLEMIRE

Explanation / Answer

Ans:

z value for 95% confidence interval is 1.96

Margin of error=1.96*sqrt(0.87*(1-0.87)/1200)=0.0190

95% CI

=0.87+/-0.0190

=(0.8510,0.8890)

b)Margin of error=1.96*sqrt(0.75*0.25/1200)=0.0245

95% CI

=0.75+/-0.0245

=(0.7255,0.7745)

c)Margin of error is not same,as sample proportion are different in both cases(margin of error depends on the sample proportion and sample size)

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