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A survey is taken among customers of a fast-food restaurant to determine prefere

ID: 2933205 • Letter: A

Question

A survey is taken among customers of a fast-food restaurant to determine preference for hamburger or chicken. Of 200 respondents selected, 75 were children and 125 were adults. 120 preferred hamburger and 80 preferred chicken. 55 of the children preferred hamburger. Find

1.the probability that a randomly selected individual is an adult is ________.

2.the probability that a randomly selected individual is an adult or a child is ________.

3.the probability that a randomly selected individual is a child and prefers chicken is ________.

4. the probability that a randomly selected individual is an adult and prefers chicken is ________.

5.assume we know the person is a child. The probability that this individual prefers hamburger is ________.

Explanation / Answer

Solution:

table:

( 1 )

the probability that a randomly selected individual is an adult = 125 / 200 = 0.625

( 2 )

the probability that a randomly selected individual is an adult or a child = (75 + 125) / 200 = 1

( 3 )

the probability that a randomly selected individual is a child and prefers chicken = 20 / 200 = 0.1

( 4 )

the probability that a randomly selected individual is an adult and prefers chicken = 60 / 200 = 0.3

( 5 )

given the person is a child , The probability that this individual prefers hamburger = 55 / 75 = 0.733

children adult total hamburgr 55 65 120 chicken 20 60 80 total 75 125 200
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