A computer repair shop has two work centers. The first center examines the compu

Question

A computer repair shop has two work centers. The first center examines the computer to see what is wrong and the second center repairs the computer. Let x, and 2 be random variables representing the lengths of time in minutes to examine a computer (x1) and to repair a computer (2). Assume , and z2 are independent random variables. Long-term history has shown the following mean and standard deviation for the two work centers: Examine computer 11 : -273 minutes; 7.5 minutes 12 : " 90.1 minutes; 153 minutes Repair computer Let W- +x2 be a rand om vanable representing the total time to examine and repair the computer. Suppose it costs S 1.80 per minute to examine the computer and $2.83 per minute to repair the computer. Then -1.80x+2.83x is a random variable representing the service charges (without parts).Compute the mean and standard deviation of V Round your answer to the nearest tenth. Oah" 304.1 2061.2 Ob,p, -1766,o,- 2061.2 0c.,-454, o,-304.1 d.4,-304 1,a,- 454 e.»,-1766,0,-454

Explanation / Answer

here mean of V =1.80*E(X1)+2.83*E(X2) =1.8*27.3+2.83*90.1 =304.1

standard deviation of V =((1.8*7.5)2+(2.83*15.3)2)1/2 =45.4

hence option d is correct

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.