A) Find the two values of the unknown constant S for which x(t) = e^ St is a sol
ID: 2945222 • Letter: A
Question
A) Find the two values of the unknown constant S for which x(t) = e^St is a solution of x'' + 6x' + 5x = 0.
Larger value of S=
Smaller value of S=
B) Consider the initial value problem x'' + 6x' + 5x = 0 with the initial condition x(0)=4 and x'(0)=-8. Find the constants c1 and c2 for which x(t) = c1 e-t + c2 e-5t satisfies the initial value problem.
c1= c2=
a. -5 b. 5 c. 1 d. -1 e. None of these
a. -5 b. 5 c. 1 d. -1 e. None of these
Explanation / Answer
a)
x'' + 6x' + 5x = 0
Characteristic eqn
^2 + 6 + 5 = 0
(+5)(+1) = 0
= -5, -1
x(t) = Ae-t + Be-5t
Larger S = -1
Smaller S = -5
b)
x(t) = = c1 e-t + c2 e-5t
x(0)=4 and x'(0)=-8
x(0) = 4 =c1 + c2
x'(t) = -c1 e-t -5c2 e-5t
x'(0) = -8 = -c1 -5c2
c1 = 3
c2 = 1
c)
x(t) = 3e-t + e-5t
x'(t) = -3e-t -5e-5t
limtx--> x'(t)/x(t) = (3e-t + e-5t) /(-3e-t -5e-5t)
limtx--> x'(t)/x(t) = (3e4t + 1) /(-3e4t -5) = -1
d)
x(t) = = c1 e-t + c2 e-5t
x(0)=1 and x'(0)=-5
x(0) = 1 =c1 + c2
x'(t) = -c1 e-t -5c2 e-5t
x'(0) = -5 = -c1 -5c2
c1= 0
c2 = 1
x'(t) = -5e-5t
x(t) = e-5t
limtx--> x'(t)/x(t) = -5e-5t /e-5t
= -5
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