um18-Math1342-A2-CRN30347-ONLINE Paola C 7/5/18 8:42 PM Test: Exam 3-over Ch 6 &
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um18-Math1342-A2-CRN30347-ONLINE Paola C 7/5/18 8:42 PM Test: Exam 3-over Ch 6 &7 Post-Test(GRADED) Time Remaining: 06:59.19 Submit Test This Question: 1 pt 12 of 20 (16 complete) ? This Test: 20 pts possible CDSS Help as of 07/ Listed below are the amounts of mercury (in parts per in tuna sushi standard deviation is 312 ppm Use technology to construct a 90% confidence interval estimate of the mean amount of mercury in the population. million, or ppm) found in tuna sushi sampled at different stores. The sample mean is 1.109 ppm and the sample ve 1.07 1.48 1.36 0.67 0.71 1.23 1.24 What is the confidence interval estimate of the mean amount of has no Round to three decimal places as needed.) mar nswer in each of the answer boxes.Explanation / Answer
Solution:- Given that mean = 1.109ppm, sd = 0.312ppm, 90% confidence
n = 7, df = n-1 = 6
t = 1.943
90% confidence interval for the population mean = X +/- t*s/sqrt(n)
= 1.109 +/- 1.943*0.312/sqrt(7)
= 0.8799 , 1.3381
= 0.880 , 1.338
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