In a recent poll, 813 adults were asked to identify their favore seat when they

Question

In a recent poll, 813 adults were asked to identify their favore seat when they fty, and 519 of tham chose a window seat Use a 0.01 significance level o test the claim that the majority of adults prefer window seats when they fty Identity the null hypothesis, altemative hypothesis, test statistic, P-value, conclusion about the nul hypothesis, and firal conclusion that addrasses the onig nal claim, Use tha P-value method and the normal distribution as an approximation to the binomial distrbution Which of he olowrng is the hypolhesis est lo be cducled? B. Hp 0.5 H: p>05 0 D. Ho: p>0.5 H1: p 0.5 OF. H: 0.5 H: p 0.5 H1 : p±0.5 H1 : p=0.5 What is the lest slalislic (Round to two decimal places as nseded.) What is the P-value? P-value (Round to three decimal places as needed.) What is the conc usion about the null hypothes s? ? A Fail to releet the null hypothesis because the P-value is less lhan or equal to the significance level, ? B. ? c. D. Raj6ct the null hypothesis because the P-value is less than or equal to the significance level, ? Rejed ihe null hypothesis because the P-value is greater than the significance leve, t Fall to reject the null hypothesis because the P-value ls greater than the significance level, ?. What is the final conclusion? A. There is sufficient wvitence to support the claim that the majority af adults prefer windaw seats when they ly. O B. There is nat sufficient evidenice to warrant rejeclion of the claim that the majority af adults prefer windaw seats when they fly. ? C There is sull caent encence to warrant rejection arele claim that the magrity of adults prefer w'ndow seats when they ny. D. There is not suicient evidence to suppcrt the clsim that the majority of adults prefer window seats when they fly

Explanation / Answer

The statistical software output for this problem is:

One sample proportion summary hypothesis test:
p : Proportion of successes
H0 : p = 0.5
HA : p > 0.5

Hypothesis test results:

Hence,

Hypotheses: Option B is correct.

z = 7.89

P - value = 0.000

Conclusion: Option B is correct.

Final conclusion: Option A is correct.

Proportion Count Total Sample Prop. Std. Err. Z-Stat P-value p 519 813 0.63837638 0.017535766 7.8910945 <0.0001

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