In a recent poll, 816 adults were asked to identify their favorite seat when the

Question

In a recent poll, 816 adults were asked to identify their favorite seat when they fly, and 501 of them chose a window seat. Use a 0.01 significance level to test the claim that the majority of adults prefer window seats when they fly. Identify the null hypothesis, altemative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. Which of the following is the hypothesis test to be conducted? OA. Ho'p#0.5 O B. Ho:p=0.5 H1 :p#0.5 O D. Ho: p0.5 C. Ho: p 0.5 H: p 0.5 OE. Ho:p> 0.5 H1 : p= 0.5 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = Round to three decimal places as needed.) What is the conclusion about the null hypothesis? 0 A. Fail to reject the null hypothesis because the P-value is greater than the significance level, . O B. Reject the null hypothesis because the P-value is greater than the significance level, . ° C. Reject the null hypothesis because the P-value is less than or equal to the significance level, . 0 D. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, . What is the final conclusion? O A. There is not sufficient evidence to warrant rejection of the claim that the majority of adults prefer window seats when they fly. 0 B. There is sufficient evidence to support the claim that the majority of adults prefer window seats when they fly ° C. There is sufficient evidence to warrant rejection of the claim that the majority of adults prefer window seats when they fly. 0 D. There is not sufficient evidence to support the claim that the majority of adults prefer window seats when they fly.

Explanation / Answer

The statistical software output for this problem is:

One sample proportion summary hypothesis test:
p : Proportion of successes
H0 : p = 0.5
HA : p > 0.5

Hypothesis test results:

Hence,

Hypotheses: Option A is correct.

z = 6.51

P - value = 0.000

Conclusion: Option C is correct.

Final conclusion: Option B is correct.

Proportion Count Total Sample Prop. Std. Err. Z-Stat P-value p 501 816 0.61397059 0.017503501 6.5113024 <0.0001

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