11. Record how much COP in a heat pump system,which originally was 3.5, decrease

Question

11. Record how much COP in a heat pump system,which originally was 3.5, decreases if the heat from the borehole to the heat pump is dropped from 8°C til 2°C, while the heat that is sent in from the heat pump continuously is 45°C Given COP of heat pump when the borehole temperature is 8°C 3.5 COP of heat pump 7, = 45 °C T1 45°C T1 - 0 112a 01 01b W. HP HP T1 (45°C) 318 K T2a (8°C) 281 K T2b (2°C) 275 K 02 02b 318 K 3.5 k 318 K- 275 K k 0.4072 Now, the new COP of HP = kli TT2b] = 0.4072118318275 R] COP 3.0116

Explanation / Answer

The original value for the coefficient of performance (COP) is given in the question.

It is said that the value of COP is later decreased from the original value which was 3.5.

We need to find what is the new value of COP.

Since all the variables is already stated in the question so there is not much of a task left as all we need to do is find the missing variable in the first equation and substitute in the next equation to get the reduced value of COP.

As the solution is given here -

We see that , in the first step - the formula of COP is entered and the required value of K is found out.

Furthermore that value of K is then used in the second equation for COP and the final COP is then calculated by susbtituting that value of K .

Formula for COP is given so we just need to substitute the values in it.

P.S - Here the values of temperature is converted from deg Celsius to Kelvin.

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.