I could use a simple detailed explanation onthis. I don\'t know to use the t dis

Question

I could use a simple detailed explanation onthis. I don't know to use the t distribution. Howdo I get my numbers? #12.

The America Sugar Producers Asso. wants to estimate the mean yearlysugar consumption. A sample of 16 people reveals the meanyearly consumption to be 60 lbs. with a standard deviation of20 lbs. a. What is the value of the populationmean? What is the best estimate of this value? b. Explain why we need to use the t-distribution. What assumption do you need tomake? c. For a 90 percent confidence interval,what is the value of t? This is the hard part forme. d. Develop the 90 percent confidenceinterval for the population mean. e. Would it be reasonalbe to concludethat the population man is 63 lbs? finally, #18. say;  Schadek Silkscreen Printing,Inc. purchases plastic cups on which to print logos for sportingevents, proms, birthdays, & other special occasions. Mr.Schade, the owner, received a large shipment today. To ensurethe quality of the shipment, he selected a random sample of 300cups. He found 15 to be defective. a. what is the estimated proportion defective in thepopulation? b. Develope a 95 percent confidence interval for theproportion defective. c. Mr. shhadek has an agreement with his supplier thathe is to return lots that are 10 percent or more defective. Should he return this lot? Please explain yourdecision. I could use a simple detailed explanation onthis. I don't know to use the t distribution. Howdo I get my numbers? #12.

The America Sugar Producers Asso. wants to estimate the mean yearlysugar consumption. A sample of 16 people reveals the meanyearly consumption to be 60 lbs. with a standard deviation of20 lbs. a. What is the value of the populationmean? What is the best estimate of this value? b. Explain why we need to use the t-distribution. What assumption do you need tomake? c. For a 90 percent confidence interval,what is the value of t? This is the hard part forme. d. Develop the 90 percent confidenceinterval for the population mean. e. Would it be reasonalbe to concludethat the population man is 63 lbs? finally, #18. say;  Schadek Silkscreen Printing,Inc. purchases plastic cups on which to print logos for sportingevents, proms, birthdays, & other special occasions. Mr.Schade, the owner, received a large shipment today. To ensurethe quality of the shipment, he selected a random sample of 300cups. He found 15 to be defective. a. what is the estimated proportion defective in thepopulation? b. Develope a 95 percent confidence interval for theproportion defective. c. Mr. shhadek has an agreement with his supplier thathe is to return lots that are 10 percent or more defective. Should he return this lot? Please explain yourdecision.

Explanation / Answer

I could use a simple detailed explanation onthis. I don't know to use the t distribution. Howdo I get my numbers? #12.

The America Sugar Producers Asso. wants to estimate the mean yearlysugar consumption. A sample of 16 people reveals the meanyearly consumption to be 60 lbs. with a standard deviation of20 lbs. a. What is the value of the populationmean?     We do notknow.What is the best estimate of this value?The sample mean 60
b. Explain why we need to use the t-distribution.  Sample size toosmall for normal What assumption do you need to make?
Almost normal
c. For a 90 percent confidence interval,what is the value of t?
degrees of freedon 16-1=15 For 90% confidence interval we100-90=10%=.1 =   This is thehard part for me. d. Develop the 90 percent confidenceinterval for the population mean.mean-t/2[s/n]<<mean +t/2[s/n]
/2=.05, for 15 degrees of freedom t.05=1.753
60- 1.753{20/16} or 60-8.765<< 60+8.756 or51.235<<68.756 e. Would it be reasonalbe to concludethat the population man is 63 lbs? 63 is in the interval, 60would be best guess, but 63 ok
finally, #18. say;  Schadek Silkscreen Printing,Inc. purchases plastic cups on which to print logos for sportingevents, proms, birthdays, & other special occasions. Mr.Schade, the owner, received a large shipment today. To ensurethe quality of the shipment, he selected a random sample of 300cups. He found 15 to be defective. a. what is the estimated proportion defective in thepopulation?
n=300 p=15/300=.005
b. Develope a 95 percent confidence interval for theproportion defective.    Large sample
P-z.025[ p(1-p)/n]or.005-1.96[.005*.995/300] 0r.005-.00798<p<.005+.00798 or 0<p<.01298,p<0
c. Mr. shhadek has an agreement with his supplier thathe is to return lots that are 10 percent or more defective. Should he return this lot? Please explain your decision. 10%is greater than .01298 or 10% not in confidence interval ... stuffis okay

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