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Help where it can be given would be greatly appreciated!! THANKS:-) 1. Participa

ID: 2954956 • Letter: H

Question

Help where it can be given would be greatly appreciated!! THANKS:-)


1. Participants enter a research study with uniquecharacteristics that produce different scores from one person toanother. For an independent-measures study, these individualsdifferences can cause problems . Briefly explain how these problemsare eliminated or reduced with a repeated-measure study.

2.

a. A repeated-measures study with a sample of n=9participants produces a mean difference of Md =4 with a standarddeviation of s = 12. Based on the mean and standard deviation youshould be able to visualize the sample distribution. Use atwo-tailed hypothesis test with x = .05 to determine whether it islikely that this sample cane from a population with uD =0.

b. Now assume that the sample standard deviation is s =3,and once again visualize the sample distribution. Use a two-tailedhypothesis test with x =.05 to determine whether it is likely thatthis sample came from a population with Ud= 0.

c. Explain how the size of the sample standard deviationinfluences the likelihood of finding a significant meandifference.

3. Research has shown that losing even one night’s sleepcan have a significant effect on performance of complex tasks suchas problem solving (Linde & Bergstroem, 1992). To demonstratethis phenomenon, a sample of n= 25 college students was given aproblem-solving task at noon on one day and again at noon on thefollowing day. The students were not permitted any sleep betweenthe two tests. For each student, the difference between the firstand second score was recorded. For this sample, the studentsaveraged MD= 4.7 points better on the firs test, with a variance ofssquare = 64 for the difference scores.

a.   Do the data demonstrate a significant change inproblem-solving ability? Use a two-tailed test with x = .05.

b.   Compute an estimate d to measure the size of theeffect.

5.   A researcher obtains a sample from an unknownpopulation and computes a sample mean of M =43 with a standarddeviation of s = 6.

a.   If the sample has n= 16 scores, compute an 80%confidence interval to estimate the unknown populationmean.

b.   If the sample has n =36 scores, computer an80& confidence interval to estimate the unknown populationmean.

c.   Comparing your answers for a and b, describe howsample size influences the width of a confidence interval.

6. Standardized measures seem to indicate that the averagelevel of anxiety has increased gradually over the past 50 years(Twenge, 2000). In the 1950s, the average score on the ChildManifest Anxiety Scale was u = 15.1. A sample of n = 16 oftoday’s children produces a mean score of M = 23.3 with SS =240.

a.   Based on the sample, make a point estimate of thepopulation mean anxiety score for today’s children.

b.   Make a 90% confidence interval estimate oftoday’s population mean.

Explanation / Answer

Figured these out for myself with some help from an onlinefriend. Thanks for all those that looked at this and was going to tryhelp!!