Calculate chi square for these two situations, which is morelikely to be \"hones
ID: 2955128 • Letter: C
Question
Calculate chi square for these two situations, which is morelikely to be "honest" A. you toss coins 6 times and lose each time B. you toss coins 60 times and win 10 times (P.S for the formula I know it is (O-E)^2/E but I am not surewhich each value is) thank you! Calculate chi square for these two situations, which is morelikely to be "honest" A. you toss coins 6 times and lose each time B. you toss coins 60 times and win 10 times (P.S for the formula I know it is (O-E)^2/E but I am not surewhich each value is) thank you!Explanation / Answer
Probability
Observed
Expected
Lose: 0.5
6
0.5 * 6 = 3
Win: 0.5
0
0.5 * 6 = 3
1.0
6
6
Find the expected frequencies.
Expected = Probability * Total
Total = 6
[(Obs – Exp)2/Exp]
= (6 – 3)2/3 +(0 –3)2/3 = 6
df = # of categories – 1
= 2 – 1 = 1
p-value= 0.014
Probability
Observed
Expected
Lose: 0.5
10
0.5 * 60 = 30
Win: 0.5
50
0.5 * 60 = 30
1.0
60
60
Find the expected frequencies.
Expected = Probability * Total
Total = 60
[(Obs – Exp)2/Exp]
= (10 – 30)2/30 +(50 –30)2/30 = 26.7
df = # of categories – 1
= 2 – 1 = 1
p-value = 0.00000024 =2.4*10-7
Probability
Observed
Expected
Lose: 0.5
6
0.5 * 6 = 3
Win: 0.5
0
0.5 * 6 = 3
1.0
6
6
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