Probability and Statistics for Engineering and the Sciences (7th) By Devore Chpa

Question

Probability and Statistics for Engineering and the Sciences (7th)
By Devore
Chpater 8, problem 36.b)
The stated answer says "Thus the probability that H0 will not be rejected using the test P=0.15 is .4920." "Thus 49.60% of all the samples will result in correct rejection of H0." Where did the 49.60% come from?
The stated answer says "Thus the probability that H0 will not be rejected using the test P=0.15 is .4920." "Thus 49.60% of all the samples will result in correct rejection of H0." Where did the 49.60% come from?

Explanation / Answer

I wish u had posted the complete problem rather thanjust the answer. If you look at z table, you will see that 0.4920 correspond to z = 2.41. Formula to convert any Normal random variable x with mean u and Std Dev s to Std Normal Distn z is z = (x-u)/std sev Hope now you can figure out how 0.4920 appears in the answer.

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.