Three people, A, B, and C are fighting in a 3-way duel (called a \"truel\") with

Question

Three people, A, B, and C are fighting in a 3-way duel (called a "truel") with pistols. When they stand at the vertices of an equilateral triangle, A can hit any of the other guys with probability 1/3, B hits with probability 2/3, and C hits with probability 1. At the beginning, they randomize the firing order with any permutation equally likely; after the first round, if at least two people are still alive, they go on in the same order. The winner is the last person to survive. For each of A, B, C, determine the probability that they win.

Explanation / Answer

please tell me the book from where this question has been taken i will give you the solution because i think there is some mistake in the question

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.