an object is released from rest (initial velocity is zero) from a sky scraper at

Question

an object is released from rest (initial velocity is zero) from a sky scraper at a hieght of 1230 ft abouve street level. hieght of object can be modeled by the position function s=f(t)= 1230 - 16t^2.....................................................................A)......... is object still falling at t=3..............................B) ..........find avg velocity of the object over the time interval from t=3 to t=4 s.......................C) .............find object instantaneous velocity at t=3

(A) yes or no ?

(B) _______________ ft/s

(C) _______________ ft/s

Explanation / Answer

s=f(t)= 1230 - 16t^2 u=0 g=32ft/s^2 since s is from ground to object distance s=0 when object reach ground solving t=sqrt(1230/16) =8.767 sec a) yes object still falling at t=3 b) avg velocity = [s'(3)+s'(4)]/2 = 112 ft/s c)instantanious = 32ft/s

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