What are the solutions to this problem? Maximum points available. thanks! Rotor
ID: 2988420 • Letter: W
Question
What are the solutions to this problem? Maximum points available. thanks!
Rotor to the largo schematic of the Fairchild I.M74I op-amp for these questions, not the schematic in the datasheet. Ql1, Q12 and R5 are the reference current generator for the circuit and the control side of two current mirrors. Ql8. Q19, and R10 generate a constant voltage across the group's terminals and may he replaced with a voltage source of value 2VBe. Ql5 O21 R6 and R7 with the help of Q24, R11 and Q22 implement an output current limiting feature. Assume node Y the bases of Q3 and Q4 is a constant voltage and therefore effectively AC-grounded. Q8. Q9, Q10 and R4 form a negative feedback loop to ensure this condition. Find the 6 transistors operated as emrtter-followers. Describe the operation of the group 05. 06. 07. R1. R2. R3. Which singl-transistor amplifier type is implemented with Q17? Which sinole-transrstor amplifier type is implemented by each of Q3 and Q4?Explanation / Answer
1) The six transitors that are emitter-followers are: Q1, Q2, Q16, Q19, Q14 and Q20.
They all have the load in the emitter and the collector connected directly to supply voltage. (Q1 and Q2 have their collector connected to the supply votlage through the current mirror Q8+Q9)
2) Q5,6,7 and R1,2,3 form a so called modified Wilson Current Mirror. The transitors Q5 and Q6 (togheter with R1 and R2) make the active load of the input differential stage (Q1,2,3,4). The Wilson current mirros has one end closed (the end from the transitor Q5) by the transitor Q7. This is done to provide a single output (on the collector of Q6) of the entire load which is otherwise simetric.
3) Q17 has as load in the collector the internal resitance provided by the current mirror (Q12+Q13b). Having the load resistance in the ollector it is called a common emitter stage. The 100 Kohm resitor in its emitter decreases gain but increases linearity.
4) Taken together Q3+Q4 are making a common base pair to eliminate the Miller Effect. Taken separately, because each Q3 and Q4 have the load in the collector (the stage decribed at point 2 above) they are connected in a common emitter configuration.
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