What is the equivalent capacitance of the circuit? For the network in Figure 2(
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Question
What is the equivalent capacitance of the circuit?
For the network in Figure 2(Figure 2) , determine the equivalent capacitance to the left of terminal a, including C4 . Assume that v1 = 6.0V , v2 = 1.0V , v3 = 4.0V , v5 = 6.0V , v6= 6.0V , C1 = 7.0?F , C2 = 5.0?F , C3 = 4.0?F , C4 = 1.0?F , C5 = 3.0?F , C6 = 1.0?F , C7 = 4.0?F , and C8 = 8.0?F .
For the network in Figure 2(Figure 2) , determine the equivalent capacitance to the right of terminal b, including C5 and C7 . Assume that v1 = 3.0V , v2 = 2.0V , v3 = 10.0V , v5 = 8.0V , v6 = 10.0V , C1 = 3.0?F , C2 = 1.0?F , C3 = 3.0?F , C4 = 9.0?F , C5 = 9.0?F ,C6 = 4.0?F , C7 = 6.0?F , and C8 = 7.0?F .
For the network in Figure 2(Figure 2) , determine the equivalent capacitance across terminalsa and b. Assume that v1 = 5.0V , v2 = 10.0V , v3 = 8.0V , v5 = 6.0V , v6 = 4.0V , C1 = 8.0?F , C2 = 2.0?F , C3 = 5.0?F , C4 = 3.0?F , C5 = 9.0?F , C6 = 5.0?F , C7 = 8.0?F , and C8 = 3.0?F .
What is the equivalent capacitance of the circuit? For the network in Figure 2(Figure 2) , determine the equivalent capacitance to the left of terminal a, including C4 . Assume that v1 = 6.0V , v2 = 1.0V , v3 = 4.0V , v5 = 6.0V , v6= 6.0V , C1 = 7.0?F , C2 = 5.0?F , C3 = 4.0?F , C4 = 1.0?F , C5 = 3.0?F , C6 = 1.0?F , C7 = 4.0?F , and C8 = 8.0?F . For the network in Figure 2(Figure 2) , determine the equivalent capacitance to the right of terminal b, including C5 and C7 . Assume that v1 = 3.0V , v2 = 2.0V , v3 = 10.0V , v5 = 8.0V , v6 = 10.0V , C1 = 3.0?F , C2 = 1.0?F , C3 = 3.0?F , C4 = 9.0?F , C5 = 9.0?F ,C6 = 4.0?F , C7 = 6.0?F , and C8 = 7.0?F . For the network in Figure 2(Figure 2) , determine the equivalent capacitance across terminalsa and b. Assume that v1 = 5.0V , v2 = 10.0V , v3 = 8.0V , v5 = 6.0V , v6 = 4.0V , C1 = 8.0?F , C2 = 2.0?F , C3 = 5.0?F , C4 = 3.0?F , C5 = 9.0?F , C6 = 5.0?F , C7 = 8.0?F , and C8 = 3.0?F .Explanation / Answer
(a) equivalent capacitance = C4 + C1 x C3 /(C1 + C3 ) = 1 uF + 28/11 uF = 39/11 uF = 3.54 uF
(b) C6 x C8 /(C6 + C8 ) + C5 x C7 /(C5 x C7 ) = 28/11 uF + 54/15 uF = 6.14 uF
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