>It is allowed to have friction in a reversible process (true or false) and why.

Question

>It is allowed to have friction in a reversible process (true or false) and why.
> If a process is in quasi-equilibrium, then it is reversible (true or false) and
why.
>It is possible to have a reversible process that is not in quasi-equilibrium (true or false) and why.
>Consider the rapid expansion of a gas in a piston-cylinder assembly between two states, 1 and 2. Show the process on a P-V diagram between the two states.
> Consider two processes on the same P-V diagram between two states, 1 and 2. The first process is reversible compression and the second process is irreversible compression in quasi-equilibrium. Cross-hatch the area that represents dissipated energy.
> The state postulate for an ideal gas states that the internal energy is function of temperature only. Thus, an isothermal compression or expansion of ideal gas is accompanied with no change in internal energy. Is it possible to compress an ideal gas isothermally and adiabatically? Justify your answer using the first law of thermodynamics.

Explanation / Answer

a) false. in reversible process no dissipative force shold be there

b) true,. becoz in quasi equilibrium process each step is executed in equilibrium , i.e. the process is carried outinfinetesmaly slowly so that every step is equlibrium, hence reversible

c) true. absence of dissipative force is another requirement for a process to be in equilibrium.

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