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Calculate the pipe diameter D in inches to 2 decimal places required to give the

ID: 2993432 • Letter: C

Question

Calculate the pipe diameter D in inches to 2 decimal places required to give the fluid velocity of 9 ft/sec in the following situation: The formula for the velocity is given by:
velocity =Flow rate / Pipe Area
And the flow rate = 8 gpm
and the Pipe Area is calculated from its diameter in inches,
231 cubic inches = 1 gallon,
12 inches = 1 ft, and
60 sec = 1 minute

Answer

1 points   

Question 2

1.       

If a volume of 23 cubic centimeters balances a mass of 29 grams on a balance, what is the specific weight w to 1 D.P.? The formula for specific weight is the weight in Newtons divided by the volume in cubic meters. 1 m = 100 cm, 1 kg weighs 9.806 Newtons, 1N = 1 kg m/s2

Answer

1 points   

Question 3

1.       

Calculate the pressure p in psi to 1 decimal place required to provide 13 horsepower to a fluid motor for the situation given below. The formula for fluid power from a 100% efficient motor is:
Power = Pressure * Flow and Flow= 59 gpm, 1 N = 1 kg*m/s2
1 gallon = 231 cubic inches, 1 HP = 550 ft*lb/sec, 12 inches =1 ft

Answer

1 points   

Question 4

1.       

Calculate the velocity v of the piston in a cylinder in km/hour to 2 decimal places. The power to be delivered to a load is 4 kW and the formula for Output power is:
Power = Force * velocity where the Force = 1,446 N, 1 W = 1 N*m/sec

Answer

1 points   

Question 5

1.       

Calculate the pump head in meters of a vane pump to 1 decimal places. The equation for pump head is:
Pump head= Pump power/(Flow rate* Specific weight)
where the Pump power= 20 kW, the Flow rate = 18 liters/sec,

and the Specific weight = 8,815 Newtons per cubic meter,
1000 liters = 1 cubic meter, and 1 kW = 1000 N*m/sec

Answer

Explanation / Answer

1)

Pipe Area = Flow rate/velocity = 1.98 ft^2

Diameter = 0.05 ft = 0.60 inches


2)

volume = 23*10^-6 m^3

mass = 29 gms = 0.029 kg

W = 0.029*9.806 N = 0.284374 N

specific wt = W/volume = 12364.0 N/m^3


3)

Flow = 59*231/(12*12*12)*60 ft^3/s

Power / Flow = Pressure in lbs = 54392.25 lb/ft^2 = 377.7 psi


4)

Power = Force * velocity

4*1000 = 1446 * v

v = 2.766 m/s = 9.96 km/hour



5)

Pump head= Pump power/(Flow rate* Specific weight)

Pump power= 20*1000 W

Flow rate = 18*10^-3 m^3/sec,

Specific weight = 8,815 Newtons / cubic meter

Pump head = 126.0 m

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