Calculate the pH of the following solutions. a) A solution containing 0.0156 M m
ID: 497354 • Letter: C
Question
Calculate the pH of the following solutions.
a) A solution containing 0.0156 M maleic acid and 0.0223 M disodium maleate. The Ka values for maleic acid are 1.20 × 10-2 (Ka1) and 5.37 × 10-7 (Ka2).
b) A solution containing 0.0246 M succinic acid and 0.015 M potassium hydrogen succinate. The Ka values for succinic acid are 6.21 × 10-5 (Ka1) and 2.31 × 10-6 (Ka2).
Calculate the pH of the following solutions. a) A solution containing 0.0156 M maleic acid and 0.0223 M disodium maleate. The Ka values for maleic 102 (Ka) and 5.37 x 07 (Kaz) acid are 1.20 Number pH b) A solution containing 0.0246 M succinic acid and 0.015 M potassium hydrogen succinate. The Ka values for succinic acid are 6.21 x 105 (Ka1) and 2.31 x 1 06 (Kaz). Number pHExplanation / Answer
pH = pKa + log [disodium malate/maleic acid]
pKa = -log Ka = -log (5.37 × 10-7) = 6.27
pH = 6.27 + log [0.0223/0.0156] = 6.11
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pKa = -logKa = -log(6.21 × 10-5) = 4.20
pH = pKa + log [Potassium hydrogen succinate/succinic acid]
= 4.20 + log[0.015/0.0246] = 3.98
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