Calculate the pH of a buffer of 1M acetic acid and 1.10M sodium acetate. Then, c

Question

Calculate the pH of a buffer of 1M acetic acid and 1.10M sodium acetate. Then, calculate pH after 0.1 mole of HCl (g) added. Assume volume doesn't change. Acetic acid Ka=1.8x10^-5. (in the second part, also please help explain how the HCl reacts). Thanks Calculate the pH of a buffer of 1M acetic acid and 1.10M sodium acetate. Then, calculate pH after 0.1 mole of HCl (g) added. Assume volume doesn't change. Acetic acid Ka=1.8x10^-5. (in the second part, also please help explain how the HCl reacts). Thanks

Explanation / Answer

If this a buffer then

pKa = -log(Ka) = -log(1.8*10^-5) = 4.75

initially

pH = pKa + log(Acetate/Acetic Acid)

pH = 4.75 + log(1.1/1)

pH = 4.79

after addition of 0.1 mol

Assume this is in 1 Liter solution

so

mol of Acid formed = 1+0.1 = 1.1

mol of acetate reacted = 1.1-0.1 = 1.0

now

pH = 4.75+ log(1.0/1.1) = 4.71

B)

HCl reacts as follows:

NaAcetetate --> Na+ + Acetate-

Acetate- + H+ --> HAcetate

which is acetic acid

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