Calculate the pH of a 7.5 times 10^-4 M Ca(OH)_2 solution. Calculate the solubil

Question

Calculate the pH of a 7.5 times 10^-4 M Ca(OH)_2 solution. Calculate the solubility of Fe(OH)_3 (Ka = 5.6 times 10^19. The values of pKa(1), pKa(2) and pka(#) for phosphoric acid, H_ PO are 2.12, 7.21 and 12.03 respectively. Write equations to show the dissociation steps in aqueous solution and assign, with reasoning, a pKa value to each step. When asked to write electron configuration for an element with 29 electrons, a student gave two answers, (Ar) 4s^1 3d^10 and (Ar)4S^2 3d^9. Which of the two answers is correct? Explain. Consider Fe(OH_2)_6^2+ and Fe(CN)^4_6 complexes, Comment on these complexes with respect to a) charge on the metal, b) high spin/low spin, c) paramagnetic/diamagnetic nature.

Explanation / Answer

Q7.

Assume Ca(OH)2 dissociates completely, then

Ca(OH)2 --> Ca2+ + 2OH-

[OH-] = 2*[Ca(OH)2]

[OH-] = 2*(7.5*10^-4) = 0.0015

pOH = -log(0.0015) = 2.823

pH = 14-pOH = 14-2.823

pH = 11.177

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.