A parachutist is in free fall at a rate of 250 km/h when he opens his parachute

Question

A parachutist is in free fall at a rate of 250 km/h when he opens his parachute at an altitude of 570 m. Following a rapid and constant deceleration, he then descends at a constant rate of 60 km/h from 556 m to 26 m, where he maneuvers the parachute into the wind to further slow his descent. Knowing that the parachutist lands with a negligible downward velocity, determine the time required for the parachutist to land after opening his parachute, the initial deceleration. t total = s a initial = m/s2

Explanation / Answer

total time =35.246 sec

initial deceleration = 162.3 m/sec2

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