Nickel has a atomic radius of .1246nm. Nickel has a atomic radius of .1246nm. 9.

Question

Nickel has a atomic radius of .1246nm.

Nickel has a atomic radius of .1246nm. 9. Nickel is FCC with an atomic radius of 0.1246nm. a. Calculate the lattice parameter b. Calculate the distance between two nearest (100) planes c. Calculate the distance between two nearest (111) planes d. Calculate the distance between two nearest (111) planes 10. In a FCC crystal with an atomic radius of 0.125nm, what is the LARGEST atom (diameter) that can fit in an interstitial site WITHOUT stressing the lattice (assume hard sphere model). Hint-check the lecture notes. Make a sketch of the model to assist you, if needed.

Explanation / Answer

in FCC,
(a)lattice parameter,

a = ( 4/sqrt2) * r

so ,
a= 2sqrt2 * 0.1246 = 0.3524 nm

(b)
distance between (100 ) planes = a ,
so ,
distance = 0.3524 nm

c)
distance between two (110) planes = sqrt 2 * a ,

distance between two (110) planes = sqrt 2 * 0.3524 = 0.4984 nm

d)

distance between two (111) planes = sqrt 3 * a ,

distance between two (111) planes = sqrt 2 * 0.3524 = 0.6104 nm

10.
largest void in FCC is octahedral void.

with ,
r(void) = 0.414 * r (atom)
r(void) = 0.414*0.125 = 0.05175 nm

so ,
diameter (void) = 0.1035 nm

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.