tained at 100 degree C. After converting the electrical signal to temperature th
ID: 2997634 • Letter: T
Question
tained at 100 degree C. After converting the electrical signal to temperature the readings are: 101.1, 99.8, 99.9, 100.2, 100.5, 99.6, 100.9, 99.7, 100.1, and 100.3. Using whatever criteria seem appropriate, make some statements about the calibration of the thermocouple. Seven students are asked to make a measurement of the thickness of a steel block with a micrometer. The actual thickness of the block is known very accurately as 2.000 cm. The seven measurements are: 2.002, 2.001, 1.999, 1.997, 1.998, 2.003, and 2.003 cm. Comment on these measurements using whatever criteria you think appropriate. A collection of 120 rock aggregate samples is taken and the volumes are measured for each. The mean volume is 6.8 cm3 and the standard deviation is 0.7 cm3. How many rocks would you expect to have volumes ranging from 5 to 7.2 cm3? Plot the equation y = 5el.2x on semilog paper. Arbitrarily assign fictitious data points on both sides of the line so that the line appears by eye as a reasonable representation. Then, using these points, perform a least-squares analysis to obtain the best fit to the points. What do you conclude from this comparison? The following data are presumed to follow the relation y = axb. Plot the values of x and y on log graph paper and draw a straight line through the points. Subsequently, obtain the values of a and b. Then, determine the values of a and b by the method of least squares. Compute the standard deviation for both cases. If a packaged computer routine for the least-squares analysisExplanation / Answer
Mean = 6.8 cm^3
S.D. = 0.7 cm^3
x = 6.5 cm^3
Z = (x - Mean) / S.D. = (6.5 - 6.8)/0.7 = -0.43
P(X<6.5) = From Normal distribution table = 0.3336
x = 7.2 cm^3
Z = (x - Mean) / S.D. = (7.2 - 6.8)/0.7 = 0.57
P(X<7.2) = From Normal distribution table = 0.7156
P( 6.5 < X < 7.2) = 0.7156 - 0.3336 = 0.382
No of rocks = 120 * 0.382 = 45.84 ~ 46
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