An ideal gas, kept in a 5-liter container at 290 kelvin, exhibits a pressure of

Question

An ideal gas, kept in a 5-liter container at 290 kelvin, exhibits a pressure of 2 atmospheres. If the volume of the container is decreased to 2.8 liters, but the temperature remains the same, what is pressure in the new container in units of atmospheres? Click the icon to view the value and units of gas constant R for Ideal Gas Law. Click the icon to view the conversion table. Click the icon to view the table of common derived units in the SI system. The new pressure is atm. (Round your answer to two significant digits.)

Explanation / Answer

PV = nRT

P1=2 atm

V1 = 5 lt

R =0.0821  atm/mol K

T=290 K

P1 *V1 = P2*V2 { n,R,T are constant here}

P2 = P1*V1/V2 = 2*5/2.8 = 3.5714 atm=3.57atm

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