results have on future advertising? 2.9 At n = 70 boutiques randomly selected th

Question

results have on future advertising? 2.9 At n = 70 boutiques randomly selected throughout the New England sales district, the following number of Rolf Laurie designer bed comforters sold last year were 2. ees $20 $24 Number of Calculate: Rolf LaurieNew England comforters sold a. Mean b. Standard boutiques (tally) (last year) deviation Modal class 0-14 1529 INIINI INI 30-44 c. b. Construct: 45-59 NN d. Histogram e. Frequency polygon 60-74 75-89 Total, 70 boutiqus histo word that 2.10 If the average amount wagered per person in state lotteries in a particular year was $100 with standard deviation $12, find the z score for a of th

Explanation / Answer

Sol:

step 1: find the mid-point for each group or range of the frequency table.
step 2: calculate the number of samples of a data set by summing up the frequencies.
step 3: find the mean for the grouped data by dividing the addition of multiplication of each group mid-point and frequency of the data set by the number of samples.
step 4: calculate the variance for the frequency table data by using the above formula.
step 5:estimate standard deviation for the frequency table by taking square root of the variance.

=sqrt(137500-{(2770)2 /70}/70-1)

s=20.104

std deviation,s=20.104

mean=total fx/n

=2770/70

=2770/70

mean =39.571

Solutionc:

The modal class (mode class) is the class with the highest frequency. In this case, the highest frequency is 23 which is the frequency for class 30-44

modal class=30-44

Rolf Laurie No of New Eng Boutiques(f) midpoint x fx fx^2 0-14 5 0+14/2=7 7 35 245 15-29 19 15+29/22 22 418 9196 30-44 23 30+44/2=37 37 851 31487 45-59 10 45+59/2=52 52 520 27040 60-74 8 60+74/2=67 67 536 35912 75-89 5 75+89/2=82 82 410 33620 Total 70 2770 137500

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