ceady done this problem. last attempt: 6.7 out of 10 gradebook: 6.7 out of 10 -p

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ceady done this problem. last attempt: 6.7 out of 10 gradebook: 6.7 out of 10 -pt this question n with last attempt is displayed for your review only Consider the function f(z) = cos(0.6(-4)). i For the value of cos(0.8(2-4) to cycle through its output values once, the value of the argument, . maat van fou du 2 The name de value olemas - ((20piy6) |- Preview ii. What is the period of function ? Preview (2plyo 6 b. Consider the function (=) = sin(dne -0.6) L. For the value of sin(x - 0.6) to cycle through its output values conce, heale of deat Mary to do the members are s- - Preview p240. GA4pl) n. What is the period of function : Preview Post this question to forum

Explanation / Answer

(a)

i)

f(x)=cos(0.6(x-4))

0 0.6(x-4) 2

=>0 (x-4) 2/0.6

=>0 (x-4) (20/6)

=>4 x 4+(20/6)

from 4 to 4+(20/6)

ii)

f(x)=cos(0.6(x-4))

=>f(x)=cos(0.6x-2.4)

period of function f =2/0.6

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b)

i)

f(x)=sin(4x -0.6)

0 (4x -0.6) 2

=>0.6 4x 2 +0.6

=>0.6/(4) x (2 +0.6)/(4)

from (0.6)/(4) to (2 +0.6)/(4)

or

from (0.6)/(4) to (1/2) +(0.6/(4))

ii)

period =2/(4)

period =1/2

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